x^2-y^2/3x^3y^3-3x^2y^4

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Solution for x^2-y^2/3x^3y^3-3x^2y^4 equation: 


x in (-oo:+oo)

x^2-(x^3*((y^2)/3)*y^3)-(3*x^2*y^4) = 0

x^2+(-1/3)*x^3*y^5-3*x^2*y^4 = 0

x^2-1/3*x^3*y^5-3*x^2*y^4 = 0

x^2*(1-1/3*x*y^5-3*y^4) = 0

1-1/3*x*y^5-3*y^4 = 0 // - 1-3*y^4

-1/3*x*y^5 = -(1-3*y^4) // : -1/3*y^5

x = (-(1-3*y^4))/(-1/3*y^5)

x = 3*y^-5*(1-3*y^4)

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in { 3*y^-5*(1-3*y^4), 0 }

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